| $$(a)\ 29+x=-2(x-13)$$ | $$(b)\ -2(x+7)-30=9x$$ | $$(c)\ -30=-37+\frac x{15}$$ |
| $$(d)\ -\frac x4-8=-48$$ | $$(e)\ 10-(x+5)=3(x+2)$$ | $$(f)\ 2(x+2)-1=3+4(x-1)$$ |
| $$(a)\ x=-1$$ | $$(b)\ x=-4$$ | $$(c)\ x=-105$$ |
| $$(d)\ x=160$$ | $$(e)\ x=-\frac14$$ | $$(f)\ x=2$$ |
| $$(a)\ 8(3x-5)-5(2x-8)=20+4x$$ | $$(b)\ x-4[x-2(x+6)]=5x+3$$ |
| $$(c)\ \sqrt5x-1=x+2$$ | $$(d)\ (x-3)(x+2)=(x-2)(x-1)$$ |
| $$(a)\ x=2$$ | $$(b)\ x\in\O$$ |
| $$(c)\ x=\frac{3(\sqrt5+1)}{4}$$ | $$(d)\ x=4$$ |
| $$(a)\ (6x-1)^2-(3x+3)^2-2(x^2-1)=(5x+2)^2$$ | $$(b)\ \frac x2-\frac x3+\frac x4=\frac x6+\frac x8+\frac x{12}+2$$ |
| $$(c)\ \frac{3-x}2-\left(\frac{7-x}3-\frac{x+3}4 \right)+\frac{7-x}{6}=\frac{9+7x}{8}-x$$ | $$(d)\ \frac{x}{2}+\frac{1}{3}\left\{\frac x4-\frac{1}{5}\left[\frac{x}{6}+\frac{1}{7}\left(\frac{x}{8}-1\right)\right]\right\}=\frac{x}{2}+\frac{x+8}{15}$$ |
| $$(e)\ \frac{1}{2}\left(3x-\frac{1}{2}\right)-\frac{1}{3}\left(4x-\frac13\right)=\frac14(6x-5)-\frac23$$ | $$(f)\ \frac{2(x-4)}3+\frac{3x+13}8=\frac{3(2x-3)}5-7$$ |
| $$(g)\ \frac{3(x+1)}{2}-\left(\frac{x+1}{4}+1\right)=\frac{5x+1}{7}-\left(\frac{3x-1}2-3\right)$$ | $$(h)\ \frac{6+25x}{15}-(x-1)=\frac{2x}3+\frac{7}5$$ |
| $$(i)\ \frac{5x+1}{4}+\frac{x-1}{6}+\frac{5x-11}{8}+\frac{4x-1}{9}=2(x+1)$$ | $$(j)\ \frac{3}{4}(x-1)-\frac23(2x-1)=2-\frac{5}6(x+1)$$ |
| $$(a)\ x=-\frac{1}{5}$$ | $$(b)\ x=48$$ |
| $$(c)\ x=1$$ | $$(d)\ x=120$$ |
| $$(e)\ x=\frac{4}{3}$$ | $$(f)\ x=49$$ |
| $$(g)\ x=\frac{5}{3}$$ | $$(h)\ x\in\mathbb R$$ |
| $$(i)\ x=7$$ | $$(j)\ x=5$$ |
| $$(a)\ \frac{2x-8}{7}+\frac{14x-3}{35}=\frac{x+3}{5}$$ | $$(b)\ 1-\frac{x-1}{\frac{2}{3}}=x$$ |
| $$(c)\ \frac{3x-5}{11}+\frac{23-x}{7}=4$$ | $$(d)\ \frac{\frac{x}{3}-\frac{x-1}{2}}{\frac{x}{3}-\frac{x+1}{4}}=x$$ |
| $$(e)\ 1-\frac{\frac{x-1}{2}}{3}=x$$ | $$(f)\ x-\frac{1-\frac{3x}{2}}{4}-\frac{3-\frac{x}{2}}{3}=2$$ |
| $$(g)\ 1+\frac{2x-1}{\frac{2}{3}}=x$$ | $$(h)\ \frac{\frac{x}{2}-\frac{2x-1}{3}}{\frac{x}{3}+\frac{3x-1}{2}}=\frac{2}{3}$$ |
| $$(a)\ x=\frac{64}{17}$$ | $$(b)\ x=1$$ |
| $$(c)\ x=9$$ | $$(d)\ x=-2$$ |
| $$(e)\ x=1$$ | $$(f)\ x=2$$ |
| $$(g)\ x=\frac{1}{4}$$ | $$(h)\ x=\frac{12}{25}$$ |
| $$(a)\ \frac{x-1}{x+1}=\frac{x-3}{x-5}$$ | $$(b)\ \frac{2x-5}{3x-4}=\frac{4x-5}{6x-1}$$ |
| $$(c)\ \frac{x+11}{x-7}+\frac{x+7}{x-11}=2$$ | $$(d)\ \frac{x+1}{x+5}+\frac{x+3}{x-1}=2$$ |
| $$(e)\ \frac{1}{x+4}+\frac{1}{3x}=\frac{1}{3x+12}$$ | $$(f)\ \frac{1}{x-3}-\frac{1}{x+2}=\frac{5}{x^2+6}$$ |
| $$(g)\ \frac{1}{x}+\frac{1}{x+1}=\frac{5}{2x+2}$$ | $$(h)\ \frac{x+1}{x-1}+\frac{2}{x+2}+1=\frac{6}{x^2+x-2}$$ |
| $$(i)\ \frac{1}{x-2}-\frac{x-3}{x+4}=\frac{6}{x^2+2x-8}-1$$ | $$(j)\ \frac{1}{x+4}+\frac{x^2-20}{x^2-6}=1$$ |
| $$(a)\ x=2$$ | $$(b)\ x=-15$$ |
| $$(c)\ x=9$$ | $$(d)\ x\in\O$$ |
| $$(e)\ x=-\frac{4}{3}$$ | $$(f)\ x=-12$$ |
| $$(g)\ x=2$$ | $$(h)\ x=-4$$ |
| $$(i)\ x\in\O$$ | $$(j)\ x=8$$ |
| $$(a)\ \frac{12}{1-9x^2}=\frac{1-3x}{1+3x}+\frac{1+3x}{3x-1}$$ | $$(b)\ \frac{3+4x}{x^2+x}-1=\frac{3}{x}-\frac{x}{x+1}$$ |
| $$(c)\ \frac{x+2}{x}+\frac{x}{x-1}=2$$ | $$(d)\ \frac{3}{x+1}=\frac{2}{x+3}+\frac{1}{x-2}$$ |
| $$(e)\ \frac{5}{3x-3}+\frac{3x+8}{4x-6}=\frac{7}{6}-\frac{6x-2}{10x-15}$$ | $$(f)\ x-3+\frac{1}{x-2}=x-4-\frac{2x-3}{2-x}$$ |
| $$(g)\ \frac{x+3}{x+1}+\frac{x+1}{x-3}=2+\frac{7x-1}{x^2-2x-3}$$ | $$(h)\ \frac{2x+19}{5x^2-5}-\frac{3x}{1-x}=3+\frac{17}{x^2-1}$$ |
| $$(a)\ x=1$$ | $$(b)\ x\in\mathbb R-\{-1,0\}$$ |
| $$(c)\ x=\frac{2}{3}$$ | $$(d)\ x=17$$ |
| $$(e)\ x=-33}$$ | $$(f)\ x\in\O$$ |
| $$(g)\ x\in\O$$ | $$(h)\ x=3$$ |
Copyright (c) 2011